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| | $issues_sql = "UPDATE issues SET assigned_to=".$fldassigned_to.", priority_id=".$fldpriority_id.", status_id=".$fldstatus_id.", version=".$fldversion.", tested=".$fldtested.", approved=".$fldapproved.", date_modified='".date("y/m/d h:i:s")."', jobCategory_id=".$fldjobCategory_id.", spent=".$fldspent;
$issues_sql = $issues_sql." WHERE issue_id=".$fldissue_id;
gives error, why? | |
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для: den
(27.04.2007 в 17:05)
| | | perform echo($issues_sql); before (or after) sending request to server, and display it here.
Also display table structure (sql-dump of table definition) please.
It is impossible to detect an error without this information . | |
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