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для: ZeeG
(16.08.2007 в 08:07)
| | | спасибо. | |
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для: sunnyday
(16.08.2007 в 08:03)
| | | Пропустили последнюю закрывающ. скобку
<?php
$user="db_vans";
$db="db_vans";
$host="db.h2m.ru";
$pass="p5sV1HAT";
if(isset($nameu) and isset($passu))
{
$link=mysql_connect($host,$user,$pass);
if(!$link)
die ("not connect");
mysql_select_db($db,$link)or die ("not open");
$table=mysql_query("SELECT * FROM users");
while ($arr=mysql_fetch_array($table))
{
if($arr['name']==$nameu)
{
echo "this name already reg";
$ex="1";
}
}
if($ex!='1')
{
$query="INSERT INTO users (name,pass) values ('$nameu','$passu')";
mysql_query($query,$link)or die ("not add <br>".mysql_error());
mysql_close($link);
echo "reg ok";
}
}
?>
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| | вот ошибка
Parse error:syntax error,unexpected $end in usr/home/vams/1/reg.php/ on line 30
а вот сам код
<?php
$user="db_vans";
$db="db_vans";
$host="db.h2m.ru";
$pass="p5sV1HAT";
if(isset($nameu) and isset($passu))
{
$link=mysql_connect($host,$user,$pass);
if(!$link)
die ("not connect");
mysql_select_db($db,$link)
or die ("not open");
$table=mysql_query("SELECT * FROM users");
while ($arr=mysql_fetch_array($table))
{
if($arr['name']==$nameu)
{
echo "this name already reg";
$ex="1";
}
}
if($ex!='1')
{
$query="INSERT INTO users (name,pass) values ('$nameu','$passu')";
mysql_query($query,$link)
or die ("not add <br>".mysql_error());
mysql_close($link);
echo "reg ok";
}
?>
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